# Resetting Cumulative Sums By Condition

Suppose you have a table** **period_end** **that indicates if a user is paying at the end of each period, like so:

period paying 1 1 2 1 3 1 4 0 5 1

You want to calculate the number of consecutive periods paying at time x. Typically, you would use a sum window function. The problem is that the window function resumes where it leaves off, like so:

period paying window_sum 1 1 1 2 1 2 3 1 3 4 0 3 5 1 4

To get the sum of *consecutive paying periods, we* actually want a result that looks like this:

period paying consec_periods 1 1 1 2 1 2 3 1 3 4 0 0 5 1 1

To get the above, we first need to identify groups of consecutive periods where paying = 1 or 0. We can do this with the lag function:

with x as ( select period , paying , case when paying = lag(paying,1) over (order by period) then 0 else 1 end as chg from period_end ) select period , paying , sum(chg) over (order by period) as grp from x

The above outputs the following:

period paying grp 1 1 1 2 1 1 3 1 1 4 0 2 5 1 3

Now, we can compute a window sum of * paying* over

*ordered by*

**grp***to get our desired output (see second table above):*

**period**with x as ( select period , paying , case when paying = lag(paying,1) over (order by period) then 0 else 1 end as chg from period_end ) , y as ( select period , paying , sum(chg) over (order by period) as grp from x ) select period , paying , sum(paying) over (partition by grp order by period) as consec_periods from y

Your period end table will likely also include a * user_id* column. Include the

*in the partition clause of the last part of the query and you're good to go!*

**user_id**-
https://stackoverflow.com/questions/20349192/reset-a-cumulative-sum -- always site sources. :-)

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